Algebra and Functions
Indices and Surds
Pearson Edexcel International Advanced Level Mathematics
Laws of indices
| Law | Statement |
|---|---|
| Multiply | am × an = am + n |
| Divide | am ÷ an = am − n |
| Power of a power | (am)n = amn |
| Zero power | a0 = 1 |
| Negative power | a−n = 1an |
| Fractional power | am/n = n√am = (n√a)m |
- A root becomes a fractional power: √x = x1/2, the nth root of x is x1/n.
- A term in the denominator becomes a negative power: 1xn = x−n.
- A power outside a bracket applies to the number as well as to x.
The form kxn
- Give one term kxn, with k and n each a simplified constant.
- Never write a power of x left in the denominator.
- Write every root as a fractional power and every reciprocal as a negative power.
- Apply any power outside a bracket to the coefficient and to the power of x.
- Combine the coefficients into one number.
- Combine the powers of x with the index laws.
- Write one term kxn.
Never write a coefficient times a root of a power of x, such as a cube root or a square root left in the term. The power is not then a simplified constant. Write the root as a fractional power, so the answer is one coefficient times x to one fractional or negative power.
Express each of the following in the form kxn, where k and n are simplified constants.
(a) 343√x (b) (25x3)−1/2
(a) 3√x = x1/3, so 34x1/3 = 34x−1/3
34x−1/3
(b) 25−1/2 = 15 and (x3)−1/2 = x−3/2
15x−3/2
Index equations
- Write both sides as powers of the same base.
- When ap = aq, then p = q: equate the powers and solve.
In this question you must show all stages of your working.
Solve 4x + 1 = 8x√2
4x + 1 = 22x + 2
8x√2 = 23x × 2−1/2 = 23x − 1/2
2x + 2 = 3x − 12
x = 52
Surds
- √a × √b = √ab and √a√b = ab
- Simplify a surd by taking out the largest square factor: √m2n = m√n.
- Rationalise 1√a by multiplying top and bottom by √a.
- Rationalise 1a + √b or 1√a + √b by multiplying top and bottom by the conjugate, the same two terms with the sign between them changed.
- Give surd answers in simplified surd form.
- Multiply by the conjugate of the denominator over itself.
- Expand the numerator, term by term.
- Use the difference of two squares on the denominator, which leaves a whole number.
- Simplify each surd in the numerator and collect like surds.
- Divide each term by the denominator.
Show that 5 + √23 − √2 can be written as 17 + 8√27
5 + √23 − √2 × 3 + √23 + √2
= 15 + 5√2 + 3√2 + 29 − 2
= 17 + 8√27
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