3.1.1 Atomic Structure
Electron Configuration
AQA A-level Chemistry
Shells and sub-shells
Electrons occupy shells, divided into sub-shells, which are made of orbitals. An orbital holds 2 electrons.
| Sub-shell | Orbitals | Electrons held | First shell |
|---|---|---|---|
| s | 1 | 2 | 1 |
| p | 3 | 6 | 2 |
| d | 5 | 10 | 3 |
The order the sub-shells fill
- Number of electrons = the atomic number, Z.
- Fill in order of increasing energy: 1s 2s 2p 3s 3p 4s 3d 4p, so 4s fills before 3d because it is lower in energy.
- Stop at Z electrons and check the superscripts add up to Z.
Writing the configuration of an ion
- Write the full configuration of the neutral atom.
- Positive ion: remove from 4s before 3d, so every transition metal ion has an empty 4s.
- Negative ion: add into the next space in the filling order.
- Check the superscripts add to Z minus the charge.
| Ion | Full electron configuration | Where the electrons went |
|---|---|---|
| Ca2+ | 1s22s22p63s23p6 | both 4s |
| Al3+ | 1s22s22p6 | the 3p, then both 3s |
| Cr3+ | 1s22s22p63s23p63d3 | the 4s, then two 3d |
| Fe2+ | 1s22s22p63s23p63d6 | both 4s, 3d untouched |
| Co2+ | 1s22s22p63s23p63d7 | both 4s |
| Cu2+ | 1s22s22p63s23p63d9 | the 4s and one 3d, from 3d104s1 |
| F− | 1s22s22p6 | one into 2p |
| Cl− | 1s22s22p63s23p6 | one into 3p |
Full configurations and the noble gas core
Write every sub-shell out from 1s, with no noble gas core. [Ar]3d9 is not a full configuration.
Chromium and copper
| Atom | Full electron configuration |
|---|---|
| Cr | 1s22s22p63s23p63d54s1 |
| Cu | 1s22s22p63s23p63d104s1 |
Each has a single 4s electron, and either order of 3d and 4s may be written.
3d44s2 is what the filling order alone predicts, and it is wrong. Chromium is 3d54s1.
Deducing the element from a configuration
- Add the superscripts for the number of electrons.
- For an ion, add the charge back: the electrons shown are not the protons.
- That total is Z. Read the symbol off the periodic table.
- 2+ ion with krypton's configuration: Sr2+.
- 2+ ion with 1s22s22p63s23p63d5: Mn, never V.
- Compound of a 2+ and a 3− ion both isoelectronic with argon: Ca3P2.
Isoelectronic species
Species that are isoelectronic have the same electron arrangement. Na+ and F− are both 1s22s22p6.
| Ion | Protons and attraction | Size |
|---|---|---|
| Mg2+ | more protons with the same electron arrangement, so a stronger attraction between the nucleus and the outer electrons | smaller |
| F− | fewer protons, so a weaker attraction | larger |
Shielding, charge density or atomic radius in place of the proton comparison is not an answer. Compare the protons first, then say the electron arrangement is the same.
The species is an ion, so write fluoride ion or F−, never fluorine. Never write that the ions have different numbers of electrons: isoelectronic means the electrons are the thing that is the same.
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